(2x^2-x-10)(4x+3)=

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Solution for (2x^2-x-10)(4x+3)= equation: 


Simplifying
(2x2 + -1x + -10)(4x + 3) = 0

Reorder the terms:
(-10 + -1x + 2x2)(4x + 3) = 0

Reorder the terms:
(-10 + -1x + 2x2)(3 + 4x) = 0

Multiply (-10 + -1x + 2x2) * (3 + 4x)
(-10(3 + 4x) + -1x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
((3 * -10 + 4x * -10) + -1x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
((-30 + -40x) + -1x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
(-30 + -40x + (3 * -1x + 4x * -1x) + 2x2 * (3 + 4x)) = 0
(-30 + -40x + (-3x + -4x2) + 2x2 * (3 + 4x)) = 0
(-30 + -40x + -3x + -4x2 + (3 * 2x2 + 4x * 2x2)) = 0
(-30 + -40x + -3x + -4x2 + (6x2 + 8x3)) = 0

Combine like terms: -40x + -3x = -43x
(-30 + -43x + -4x2 + 6x2 + 8x3) = 0

Combine like terms: -4x2 + 6x2 = 2x2
(-30 + -43x + 2x2 + 8x3) = 0

Solving
-30 + -43x + 2x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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